(X^2+4x+4)10=40(2+x)

Solution for (X^2+4x+4)10=40(2+x) equation:

Simplifying
(X2 + 4x + 4) * 10 = 40(2 + x)

Reorder the terms:
(4 + X2 + 4x) * 10 = 40(2 + x)

Reorder the terms for easier multiplication:
10(4 + X2 + 4x) = 40(2 + x)
(4 * 10 + X2 * 10 + 4x * 10) = 40(2 + x)
(40 + 10X2 + 40x) = 40(2 + x)
40 + 10X2 + 40x = (2 * 40 + x * 40)
40 + 10X2 + 40x = (80 + 40x)

Add '-40x' to each side of the equation.
40 + 10X2 + 40x + -40x = 80 + 40x + -40x

Combine like terms: 40x + -40x = 0
40 + 10X2 + 0 = 80 + 40x + -40x
40 + 10X2 = 80 + 40x + -40x

Combine like terms: 40x + -40x = 0
40 + 10X2 = 80 + 0
40 + 10X2 = 80

Solving
40 + 10X2 = 80

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + 10X2 = 80 + -40

Combine like terms: 40 + -40 = 0
0 + 10X2 = 80 + -40
10X2 = 80 + -40

Combine like terms: 80 + -40 = 40
10X2 = 40

Divide each side by '10'.
X2 = 4

Simplifying
X2 = 4

Take the square root of each side:
X = {-2, 2}